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Two metallic wires A and B of the sauce material are connected in parallel. Wire A has the length 'L' and radius 'r' and wire B has the length '2L' and radius '2r'. Compute the ratio of total resistance of parallel combination to the resistance of wire A. |
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Answer» Answer: 1:2. Explanation: R1=(RHO)L/A. R2=(rho)2L/2A. 2 and 2 CANCEL each other. R2=(rho)L/A. Hence, R1=R2. In PARALLEL combination, Total 1/R=1/R1 + 1/R2...........(1) Since R1=R2, R=R1/2.(KEEPING VALUE of R2=R1 in (1)). Ratio R:R1=1:2. |
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