1.

Two men start from points A and B respectively , 42 km apart. One walks from A to B at 4km/hr and another walks from B to A at a certain uniform speed . They meet each other after 6 hours . Find the speed of the second man . Please give answer in proper solution...

Answer»

Answer:

3 km /hr

Step-by-step explanation:

Distance between A and B is 42 km

ONE walks from A to B at 4 km/hr

Another walks from B to A at a certain uniform speed .

They meet each other after 6 hours .

Distance traveled by first in 6 hours = Speed \times Time = 4 \times 6=24km

So, The distance traveled by first from Point A is 24 km

So, remaining distance = 42-24=18 km

So, A PERSON who starts from point B has traveled 18 km TILL the point where they meet.

So, Distance traveled by second one in 6 hours = 18 km

So, Speed of second one = \frac{distance}{time}

                                           = \frac{18}{6}    

                                           = 3    

Hence the speed of the second man is 3 km /hr


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