1.

Two masses m_(1) = 4.8 kg and m_(2) = 5 kg tied to a string are hanging over a light frictionless pully. What is the acceleration of masses when they are free to move ?

Answer»

0.2 `m//s^(2)`
9.8 `m//s^(2)`
5 `m//s^(2)`
4.8 `m//s^(2)`

SOLUTION :Supposethe accelerationof compositesystemis a
`m_(2) g - T =m_(2)a ` and
Addingthesetwoequations
`(m_(2)-m_(1)) g =(m_(1) =m_(2)) a`
`a= ((m_(2) - m_(1))/(m_(1) + m_(2))) g `

`=((5-4.8)/( 5+4.8)) 9.8`
`=(0.2)/(9.8) xx 9.8`
`a= 0.2 m//s^(2)`


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