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Two masses A and B of 3kg and 2kg are connected by a long inextensible string which passes over a massless and frictionless pulley. Initially the height of both the masses from the ground is same and equal to 1 metre. When the masses are released. Mass A hits the ground and gets stuck to the ground. Consider the length of the string as large, so that the pulley does not obstruct the motion of masses A and B `[g = 10 m//s^(2)]` A. The impulse A exerts on ground is `6N-S`B. The impulse A exerts on ground is 2N-SC. B reaches a maximum height of 2.2 m from the groundD. B reaches maximum height from the ground 1.2 sec after being released. |
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Answer» Correct Answer - A::C::D `a=(3-2)/(3+2)g=2m//s^(2)` gtbrgt `V^(2)=u^(2)+2as rArr V^(2)=2xx2xx1 rArr V=2m//s` Impulse A exterts `J = 3 xx 2 = 6N-S` For block B, `0 - (2)^(2) = 2(-10)S` `S = 0.2 m` `S = ut(1) + (1)/(2) at_(1)^(2)` `1 = (1)/(2) 2t_(1)^(2)" "t_(2) = 0.2 S` |
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