1.

Two magnetic poles of pole strength 20 Am and 15 Am are kept at a distance of 10cm. The force acting on one of the poles is ...... ..

Answer»

`3 xx 10^(2)` N
`3 xx 10^(-3)` N
`2 xx 10^(-3)` N
`3 xx 10^(-5)` N

Solution :Here `P_(1) = 20 "Am", P_(2) = 15 "Am"`,
`r= 10 cm = 10 xx 10^(-2) `m
`F = (mu_0)/( 4pi ) . (P_1 P_2)/( r^2) `
`= (4pi xx 10^(-7) )/( 100 xx 10^(-4)) THEREFORE F=3 xx 10^(-3) N`


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