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Two lock gates of `7.5 m` height are provided in a canal of `16 m` width meeting at an angle of `120^@`. Calculate the force acting on each gate when the depth of water in upstream side is `5 m`. |
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Answer» Height of lock gates `=7.5m` Width of canal `=16m` Inclination of gates `=120^@` and `H=5m` From the geometry of the lock gates, we find that inclination of the lock gates with the walls `a=(180^@-120^@)/2=30^@` and width of each gate `=(16/2)/(cosalpha)=8/(cos30^@)=8/0.866=9.24m` Therefore, wetted area of each gate `A=5xx9.24=46.2m^(2)` and force acting on each gate is `F=gAxx(H/2)=9.81xx46.2xx(5/2)=1133kN` |
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