1.

Two liquids A and B have vapour pressure of 500 mm Hg and 200 mm Hg respectively. Calculate the mole fraction of A at which two liquids have equal partial pressures.

Answer»


SOLUTION :`"For liquid A" , P_(A)=P_(A)^(@)orP_(A)=500 mm X_(A)`
`"For liquid B", P_(B)=P_(B)^(@)X_(B)or P_(B)=P_(B)^(@)(1-x_(A))=200MM(1-x_(A))`
SINCE the VAPOUR pressures of the two liquids are to be same, `P_(A)=P_(B)`
`Therefore 500x_(A)=200 (1-x_(A))or X_(A)=200/700=0.286`
Mole fraction of A at which the two liquids have equal partial pressures = 0.286.


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