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Two liquids `A` and `B` have `P_(A)^(@)` and `P_(B)^(@)` in the ratio of `1:3` and the ratio of number of moles of `A` and `B` in liquid phase are `1:3` then mole fraction of `A` in vapour phase in equilibrium with the solution is equal to :A. 0.1B. 0.2C. 0.5D. `1.0` |
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Answer» Correct Answer - A `X_(A)=(1)/(4),X_(B)=(3)/(4)` `P_("total")=P_(A)^(@)X_(A)+P_(B)^(o)X_(B)` ` =1xx(1)/(4)+3xx(3)/(4)` ` =(1)/(4)+(9)/(4)=(10)/(4)=(5)/(2)` `Y_(A)=(P_(A)^(@)X_(A))/(P_("total"))=(4)/((5)/(2))=(2)/(20)=(1)/(10)=0.1` |
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