Two lighter nuclei combine to form a comparatively heavier nucleus by

1.	Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: \(_1^2X + _1^2X = \,_2^4Y\)The binding energies per nucleon \(_1^2X\) and \(_2^4Y\) are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is _____ MeV.
Answer» Energy released in the given process = Binding energy of product – Binding energy of reactants = 7.6 × 4 – (1.1 × 2) × 2 = 30.4 – 4.4 = 26 MeV

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: \(_1^2X + _1^2X = \,_2^4Y\)The binding energies per nucleon \(_1^2X\) and \(_2^4Y\) are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is _____ MeV.

Answer»

Energy released in the given process = Binding energy of product – Binding energy of reactants

= 7.6 × 4 – (1.1 × 2) × 2

= 30.4 – 4.4

= 26 MeV

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Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: \(_1^2X + _1^2X = \,_2^4Y\)The binding energies per nucleon \(_1^2X\) and \(_2^4Y\) are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is _____ MeV.

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