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Two inductances connected in parallel are equivalent to a single inductance of `1.5H` and when connected in series are equivalent to a single inductance of 0.8 H. The difference in their inductance isA. 3 HB. 7.5 HC. 2 HD. 4 H |
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Answer» Correct Answer - D `therefore` In parallel, `L_(P)=(L_(1)L_(2))/(L_(1)+L_(2))` `(L_(1)+L_(2))1.5=L_(1)L_(2)` and in series, `L_(s)=L_(1)+L_(2)=8` `therefore" "L_(1)L_(2)=12` `(L_(1)-L_(2))^(2)=(L_(1)+L_(2))^(2)-4L_(1)L_(2)` `L_(D)=sqrt((8)^(2)-4xx12)` `L_(D)=4 H` |
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