1.

Two identically charged particles are fastened to the two ends of a spring ofspring constant 100 N m ^(-8) C, find the extension In the length of the apring. Assume that the extension is small as scompared to the natural length . Justify this assumption after you solve the problem.

Answer»

SOLUTION :`ELECTRIC force = spring force `
` 1/(4piepsilon_0)(q^2 )/(x+0.1)^2=K(0.1+x) `
` or (0.1+x)^3=(9xx10^9xx(2.0xx10^-8)^2)/10^-2 `
` = (36xx10^9xx10^-16) /10^-2 `
`= 36xx10^-5 `
` or x=3.6xx10^-6m `


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