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Two identical slabs, of a given metal, are joined together, intwo different ways, as shown in Fig.(i) and (ii). What isthe ratio of the resistances of these two combinations ? |
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Answer» Solution :Let each slab has LENGTH l and cross-section AREA A. Then in combination (i), `R_1 = (rho 2l)/(A)` and in combination (II), `R_2 =(rho l)/(2A)` `RARR R_1/R_2 =4/1 " or"R_1 = 4R_2` |
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