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Two identical rings each of mass m with their planes mutually perpendicular, radius R are welded at their point of contact O. If the system is free to rotate about an axis passing through the point P perpendicular to the plane to the paper, the moment of inertia of the system about this axis is equal to A. `6.5mR^(2)`B. `12mR^(2)`C. `6mR^(2)`D. `11.5mR^(2)` |
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Answer» `I=I_(1)+I_(2)=[2mR^(2)]+[(mR^(2))/(2)+m(3R)^(2)]` `=11.5mR^(2)` |
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