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Two identical heaters rated `220 V , 1000 W` are paced in series with each other across `220 V` line , then the combined power is |
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Answer» For series combination, the total power (P) is `1/P = 1/P_(1) + 1/P_(2)` or `P = (P_(1)+P_(2))/(P_(1) + P_(2)) = (1500 xx 1500)/(1500+1500)= 750W` |
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