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Two identical constaners A and B having same volume of an ideal gas at same temperature hace mass of the gas as `m_(1)` and `m_(2)` respectively and `2m_(1) = 3m_(2)`. The gas in each cylinder expands isomthermally to double of its voume. If change in pressure in A is `300 Pa`, then the change in pressure in B isA. `200 Pa`B. `300 Pa`C. `400 Pa`D. `500 Pa` |
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Answer» Correct Answer - A `2m_(1) = 3m_(2)` `P_(1)V = (m_(1))/(M) RT` and `P_(2)V = (m_(2))/(M)RT = (2)/(3)(m_(1))/(M)RT` `(P_(1))/(P_(2)) = (3)/(2)` The process is isothermal `(P_(1)V_(1) = P_(2)v_(2))` Hence, `DeltaP_(1) = P_(1) - (P_(1))/(2) rArr P_(1) = 2DeltaP_(1)` `DeltaP_(2) = P_(2) - (P_(2))/(2) = (P_(2))/(2) = (1)/(2)(2)/(30P_(1) = (P_(1))/(3)` `DeltaP_(2) = (2)/(3) DeltaP_(1) = (2)/(3).300` `DeltaP_(2) = 200 pa` |
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