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Two ice skaters A and B approach each other at right angles. A has mass 30 kg and velocity 1 m/s and B has a mass of 20 kg and velocity 2 m/s. They meet and stick together. The final velocity of couple is : |
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Answer» SOLUTION :LET v = Composite velocity after collision, `theta = angle` with the direction of 30 kg mass Then from momentum conservation, `50v cos theta = 30xx1` `50v SIN theta = 20 xx2` From equations (1) and (2), `sqrt((50)^(2)+v^(2))=sqrt(900+1600)` `50v=50` v = 1 m/s.
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