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Two guns are pointed at each other one upwards at an angle of elevation of `30^(@)` and the other at the same angle of depression, the muzzels being 30 meter apart. If the bullets leave the guns with velocities of 350 meters per second and 300 meters per second respectively. find when will they meet. Take g=9.8 meters per `"sec"^(2)`. A. 3/65 secB. 5/65 secC. 3/95 secD. `sqrt(3)/1` sec |
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Answer» `t=(s_("rel"))/(U_("rel"))=(30)/(650)` `therefore t=(3)/(65)sec`. |
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