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Two glasses with refractive indices of 1.5 and 1.7 are used to make two identical double convex lenses how will each of these lenses act on a ray parallel to its optical axis |
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Answer» 1/fa =(1.5 - 1)(1/R1 - 1/R2) ----(1) 1/fa =(1.5 - 1)(1/R1 - 1/R2) ----(1)1/fb =(1.7 - 1)(1/R1 - 1/R2) -----(2) 1/fa =(1.5 - 1)(1/R1 - 1/R2) ----(1)1/fb =(1.7 - 1)(1/R1 - 1/R2) -----(2)On DIVIDING EQ(2) by EQ {1) we get, fa/fb = 7/5 |
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