1.

Two girls move in opposite directions, one from A to B and other from B to A. The girl from A reaches the destination in 16 hrs and girl from B reaches her destination in 25 hrs, after having met. If former's speed is 25 km/hr, what will be the speed of latter?​

Answer»

The speed of the latter is 20 km/h

Step-by-step explanation:

Let the speed of the girl going from B to A be v km/hr

The DISTANCE between A to B = AB

Let the girl from A has travellevd distance = d before meeting the girl from B

According to the question

Girl from A takes 16 hours and girl from B takes 25 hours after they meet to reach their destination

Speed of girl from A = 25 km/hr

Using Distance = Speed × Time

AB-d={25}\times{16}

Again

d=25\times v

Dividing both we get

\frac{AB-d}{d}=\frac{25\times 16}{25\times v}

\implies \frac{AB}{d}-1=\frac{16}{v}   ....... (1)

If they meet after time t

Then in time t, the girl from A has travelled distance = d

And the girl from B has travelled distance = AB - d

Thus

d=25\times t

And AB-d=v\times t

From the above two equations

\frac{AB-d}{d}=\frac{vt}{25t}

\implies \frac{AB}{d}-1=\frac{v}{25}   ...... (2)

From equations (1) and (2)

\frac{16}{v}=\frac{v}{25}

\implies v^2=16\times 25

\implies v=\sqrt{16\times 25}=4\times 5=20 km/h

Therefore, the speed of girl from B is 20 km/h

Hope this answer is helpful.

Know More:

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