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Two friends bought two bicycles whoseprices were in the ratio of 1:5. If theysold them at a loss of 10%. thedifference of the money earned by themwas Rs. 3600. What was the cost price ofthe costlier cycle? |
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Answer» Let cost of first cycle be xLet cost of second cycle be 5x Selling price of first cycle SP1= x(1 - 10/100)= 9x/10 Selling price of second cycle SP2= 5x(1 - 10/100)= 5x*9/10= 45x/10 Now,SP2 - SP1 = 3600(45x - 9x)/10 = 360036x = 36000x = 36000/36 = 1000 Therefore, cost price of costlier cycle= 5x = 5*1000= Rs 5000 |
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