Two friends bought 100 articles and divided them on a condition such t

1.	Two friends bought 100 articles and divided them on a condition such that each will have to sell his share at a profit % numerically equal to number of articles. In what ratio should they divide the articles to earn an overall profit of 58%.1). 3 : 72). 4 : 53). 5 : 74). 2 : 3
Answer» Let FIRST person took x article and other took (100 – x) And price of each article is 100 x article will be SOLD at a profit of x% and (100 – x) article will be sold at a profit of (100 – x)% So, overall profit = 58x100 = [(x)(x) + (100 – x) (100 – x)] 58 × 100 = x² + 10000 + x² - 200x x² - 100x + 2100 = 0 x = 30, 70 So, the RATIO of their article is 3: 7 Short trick To save time, USE option method: Let the first person has 30 article then other has 70 ⇒ (30 × 30 + 70 × 70)/100 = 5800/100 = 58%

Two friends bought 100 articles and divided them on a condition such that each will have to sell his share at a profit % numerically equal to number of articles. In what ratio should they divide the articles to earn an overall profit of 58%.1). 3 : 72). 4 : 53). 5 : 74). 2 : 3

Answer»

Let FIRST person took x article and other took (100 – x)

And price of each article is 100

x article will be SOLD at a profit of x% and (100 – x) article will be sold at a profit of (100 – x)%

So, overall profit = 58x100 = [(x)(x) + (100 – x) (100 – x)]

58 × 100 = x² + 10000 + x² - 200x

x² - 100x + 2100 = 0

x = 30, 70

So, the RATIO of their article is 3: 7

Short trick

To save time, USE option method:

Let the first person has 30 article then other has 70

⇒ (30 × 30 + 70 × 70)/100 = 5800/100 = 58%

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Two friends bought 100 articles and divided them on a condition such that each will have to sell his share at a profit % numerically equal to number of articles. In what ratio should they divide the articles to earn an overall profit of 58%.1). 3 : 72). 4 : 53). 5 : 74). 2 : 3

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