two equal sides of triangle are each 5m less than twice the third side

1.	two equal sides of triangle are each 5m less than twice the third side.If the perimeter of the triangle is 55 metre,find the length of its sides
Answer» ANSWER: LET the THIRD side of TRIANGLE be X 1st side= 2X-5 2nd side=2X-5 Perimeter of triangle= Sum of all sides (2X-5)+(2X-5)+X = 55 5X-10 = 55 5X = 55+10 5X = 65 X = 65/5 X= 13 1st side = 2X-5 = 2*13-5 =21 2nd side = 21 3rd side= 13

two equal sides of triangle are each 5m less than twice the third side.If the perimeter of the triangle is 55 metre,find the length of its sides

Answer»

ANSWER:

LET the THIRD side of TRIANGLE be X

1st side= 2X-5

2nd side=2X-5

Perimeter of triangle= Sum of all sides

(2X-5)+(2X-5)+X = 55

5X-10 = 55

5X = 55+10

5X = 65

X = 65/5

X= 13

1st side = 2X-5

= 2*13-5

=21

2nd side = 21

3rd side= 13

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two equal sides of triangle are each 5m less than twice the third side.If the perimeter of the triangle is 55 metre,find the length of its sides​

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two equal sides of triangle are each 5m less than twice the third side.If the perimeter of the triangle is 55 metre,find the length of its sides