Two equal masses are connected by a spring satisfying Hooke's law and are placed on a frictionless table. The spring is elongated a little and allowed to oscillate. Let the angular frequency of oscillations be ω. Now one of the masses is stopped. The square of the new angular frequency is ω2x, where x is

Two equal masses are connected by a spring satisfying Hooke's law and

1.	Two equal masses are connected by a spring satisfying Hooke's law and are placed on a frictionless table. The spring is elongated a little and allowed to oscillate. Let the angular frequency of oscillations be ω. Now one of the masses is stopped. The square of the new angular frequency is ω2x, where x is
Answer» Two equal masses are connected by a spring satisfying Hooke's law and are placed on a frictionless table. The spring is elongated a little and allowed to oscillate. Let the angular frequency of oscillations be $ω$ . Now one of the masses is stopped. The square of the new angular frequency is $\frac{ω^{2}}{x}$ , where $x$ is

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