Two elements, X (Atomic mass 16) and Y (Atomic mass 14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with fixed mass of X in A, B and C is 1:3:5. If 32 parts by mass of X combine with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with _______. (A) 14 parts by mass of Y (B) 42 parts by mass of Y (C) 70 parts by mass of Y (D) 82 parts by mass of Y

Two elements, X (Atomic mass 16) and Y (Atomic mass 14) combine to for

1.	Two elements, X (Atomic mass 16) and Y (Atomic mass 14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with fixed mass of X in A, B and C is 1:3:5. If 32 parts by mass of X combine with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with _______. (A) 14 parts by mass of Y (B) 42 parts by mass of Y (C) 70 parts by mass of Y (D) 82 parts by mass of Y
Answer» c) 70 PARTS by mass of YExplanation:NUMBER of ELEMENTS = 2 = X and YNumber of compounds = 3 = A B and CIn B, 32 parts of X combine with Y = 84 PARTS16 parts of X combine with Y = 42 partsThe number of parts of X in both B and C is of equal to the MASSES of Y combining with a fixed mass of X in B and C in ratio 3:5Mass of Y in B / Mass of y in C =3/5 = 42 parts / Mass Y in C = 3/5Mass of Y in C = 5/3×42 =70 partsThus, parts by mass of X will combine with 70 parts by mass of Y