1.

Two electric poles of equal heights are opposite to each other on either side of a road. Width of the roadis 100 metres. The angles of elevations from the point, between two poles on the road to the tops of the poles are 30° and 60° Find the height of the pole and the distance of that point from each pole​

Answer»

Answer:

The distance of point C

AC=x=75 m

QC=25 m

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height of each pole=25√3 m

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Step-by-step explanation:

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As per in the FIGURE  AB and PQ are two poles on the road BQ

from Cthe angle of elevation are 30 and 6 degree

let BC=x the CQ=100-x

In the ΔABC

AB/x=tan 30=1/√3

AB=x/√3..........................(1)

In the Δ PQC

PQ/(100-x) =tan 60=√3

PQ= √3( 100-x)...........................(2)

As per question

PQ=AB

So x/√3=√3( 100-x)

x=√3*√3( 100-x)

=3(100-x)

x=300-3x

4x=300

x=300/4=75 m

So The distance of point C

AC=x=75 m

QC=25 m

From(1)

AB=75/√3=75√3/√3*√3

=75√3/3=25√3

So height of each pole=25√3 m


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