Two electric bulbs whose resistances are in the ratio of `1:2` are connected inparallel to a constant voltage source. The powers dissipated in them have the ratio

Two electric bulbs whose resistances are in the ratio of `1:2` are con

1.	Two electric bulbs whose resistances are in the ratio of `1:2` are connected inparallel to a constant voltage source. The powers dissipated in them have the ratio
Answer» Let resistance of bulbs are R and 2R Power dissipated `P=(V^(2))/(R) therefore P_(1)=(V^(2))/(R)` and `P_(2)=(V^(2))/(2R) therefore (P_(1))/(P_(2))=(2)/(1)`

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Two electric bulbs whose resistances are in the ratio of `1:2` are connected inparallel to a constant voltage source. The powers dissipated in them have the ratio

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