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Two elastic waves move along the same direction in the same medium. The pressure amplitudes of both the waves are equal, but the wavelength of the first wave is three times that of the second. If the average power transmitted through unit area by the first wave is `W_(1)` and that by the second is `W_(2)`, thenA. `W_(1)=W_(2)`B. `W_(1)=3W_(2)`C. `W_(2)=3W_(1)`D. `W_(1)=9W_(2)` |
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Answer» Correct Answer - A `I=(Power)/(Area)=(P_(0)^(2))/(2rhov)` `I=I_(f)=I_(2)` `w_(1)=w_(2) Ans. (A)` |
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