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Two discs of same moment of inertia rotating their regular axis passing through centre and perpendicular to the plane of disc with angular velocities `omega_(1)` and `omega_(2)`. They are brought into contact face to the face coinciding the axis of rotation. The expression for loss of enregy during this process is :A. `(1)/(4) I (omega_(1) - omega_(2))^(2)`B. `I (omega_(1) - omega_(2))^(2)`C. `(1)/(8)(omega_(1) - omega_(2))^(2)`D. `(1)/(2) I (omega_(1) + omega_(2))^(2)` |
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Answer» Loss of energy `Delta K - (1)/(2) (I . I)/(I + I) (omega_(1) - omega_(2))^(2)` ` = (1)/(4) I (oemga_(1) - omega_(2))^(2)` |
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