1.

Two discs have same mass and thickness. Their materials are of densities d_(1) and d_(2). The ratio of their moments of inertia about an axis passing through the centre and perpendicular to the plane is

Answer»

`d_(1) : d_(2)`
`d_(2):d_(1)`
`((d_(1))/(d_(2)))^(2)`
`((d_(2))/(d_(1)))^(2)`

SOLUTION :We have, `(PIR^(2)td)=m""(because "mass = density" xx "volume")`
`R^(2)=(m)/(PID)`
Now, `I=(1)/(2)mR^(2)=(m^(2))/(2pitd)or I prop (1)/(d)`
`:.` The RATIO of moments of inertia, `(I_(1))/(I_(2))=(d_(2))/(d_(1))`.


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