Two dice are thrown simultaneously the probability of getting a sum of

1.	Two dice are thrown simultaneously the probability of getting a sum of 11
Answer» ANSWER: $\red\bigstar$ PROBABILITY of getting a sum of 11 when two dice are thrown simultaneously = 1/18. SOLUTION SAMPLE SPACE WHEN 2 DIE ARE THROWN (1,1) , (2,1) , (3,1) , (4,1) , (5,1) , (6,1) (1,2) , (2,2) , (3,2) , (4,2) , (5,2) , (6,2) (1,3) , (2,3) , (3,3) , (4,3) , (5,3) , (6,3) (1,4) , (2,4) , (3,4) , (4,4) , (5,4) , (6,4) (1,5) , (2,5) ,(3,5) , (4,5) , (5,5) , (6,5) (1,6) , (2,6) , (3,6) , (4,6) , (5,6) , (6,6) $\boxed{\sf Probability \:of \:an \:event = \dfrac{Number \:of \:<klux>FAVORABLE</klux> \:outcomes}{Total \:number \:of \:Outcomes} }$ We are ASKED to find the probability of getting a sum of 11 . ✳ Favorable Events of getting a sum of 11 = (6,5) and (5,6) ✳ Number of Favorable Events = 2 ✳ Total Number of events = 6² = 36 Events. $\sf Probability \: of \: getting\: a \: sum \: of \: 11 = \dfrac{2}{36}$ $\implies$ $\sf Probability \: of \: getting\: a \: sum \: of \: 11 = \dfrac{1}{18}$

Two dice are thrown simultaneously the probability of getting a sum of 11

Answer»

$\red\bigstar$ PROBABILITY of getting a sum of 11 when two dice are thrown simultaneously = 1/18.

(1,1) , (2,1) , (3,1) , (4,1) , (5,1) , (6,1)

(1,2) , (2,2) , (3,2) , (4,2) , (5,2) , (6,2)

(1,3) , (2,3) , (3,3) , (4,3) , (5,3) , (6,3)

(1,4) , (2,4) , (3,4) , (4,4) , (5,4) , (6,4)

(1,5) , (2,5) ,(3,5) , (4,5) , (5,5) , (6,5)

(1,6) , (2,6) , (3,6) , (4,6) , (5,6) , (6,6)

$\boxed{\sf Probability \:of \:an \:event = \dfrac{Number \:of \:<klux>FAVORABLE</klux> \:outcomes}{Total \:number \:of \:Outcomes} }$

We are ASKED to find the probability of getting a sum of 11 .

✳ Favorable Events of getting a sum of 11 = (6,5) and (5,6)

✳ Number of Favorable Events = 2

✳ Total Number of events = 6² = 36 Events.

$\sf Probability \: of \: getting\: a \: sum \: of \: 11 = \dfrac{2}{36}$

$\implies$

$\sf Probability \: of \: getting\: a \: sum \: of \: 11 = \dfrac{1}{18}$