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Two dice are rolled simultaneously. Find the probability that the sum is more than and equal to 10 or 12Experts plz answer step by step...

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When two DICE rolled simultaneously

TOTAL OUTCOMES = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Total number of outcomes = 6 x 6 = 36

FAVOURABLE outcomes = {(4,6),(5,5),(6,4),(5,6),(6,5),(6,6)}

Number of favourable outcomes = 6

Probability = favourable outcomes/total outcomes

Probability = 6/36 = 1/6


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