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Two cylindrical rods of uniform cross-section area `A` and `2A`, having free electrons per unit volume `2n` and `n` respectively are joined in series. A current `I` flows through them in steady state. Then the ratio of drift velocity of free electron in left rod to drift velocity of electron in the right rod is `((v_(L))/(v_(R)))` is A. `1//2`B. 1C. 2D. 4 |
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Answer» Correct Answer - B b. Since current `In eAV_(d)` through both the rods is the same, i.e., `2(n) eAv_(L) = n e(2A)v_(R)` `v_(L)/v_(R) = 1 ` . |
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