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two cyclist A and B start from the junction of two roads inclined at 90°,the ratio of their velocities being 3:4.find the ratio of the rate at which two cyclist are seperating with the velocity of A. |
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Answer» HEY DEAR HERE IS YOUR ANSWER ✌ ✌❤ ❤ Since the two cyclists have a 3:43:4 ratio of velocities, we assume they are 3v,4v correspondingly. Then, the distance of CYCLIST A from the intersection is given by d1=3vt. In the same way, the distance of cyclist B from the intersection is given by d2=4vt. By Pythagorean's theorem we know the distance between the two cyclists is d= √d² 1 +d² 2−−−−−−√=5vtd=d12+d22=5vt. Thus, the rate at which two cyclists are separating can be found by taking derivative of dd with respect to time tt. ddt5vt=5vddt5vt=5v Therefore, the ratio ratio of the rate at which two cyclists are separating with the VELOCITY of A should be 5v3v=535v3v=53. You GOT it! |
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