Step-by-step explanation:

The question is not very clear

If you mean that the VOLUME of the cube is 64 cm³ then

Volume of a cube = a³

Where a = SIDE of the cube

=> a³ = 64

=> a = ∛64

=> a = 4 cm

Now the dimensions of the resulting cuboid formed by joining the ENDS of the cubes are

Length = 4+4 = 8 cm

Breadth = 4 cm

Height = 4 cm

Surface area of the cuboid = 2 * [ (l*b) + (b*h) + (l*h) ]

Where l, b, and h, are the length, breadth, and height of the cuboid respectively

Substhe values and solving, we get

Surface area = 2*[ (4*8) + (4*4) + (8*4) ] = 2 * [ 32 + 32 + 16 ] = 2 * 80 = 160 cm²

Therefore, the surface area = 160 cm²

Now, if you mean the surface area of the cube = 64 cm², then

Surface area of a cube = 6 * a²

Where a = side of the cube

=> 6 * a² = 64

=> a² = 64/6

=> a = √(64/6) = 8/√6 = 8/2.4 = 10/3 = 3.3 cm

Now, by joining the cubes together, the new dimensions are

Length = 3.3 + 3.3 = 6.6

Breadth = 3.3

Height = 3.3

The surface area of the cuboid = 2 * [ (3.3*6.6) + (3.3*3.3) + (6.6*3.3) ]

= 2 * [ 21.78 + 21.78 + 10.89]

= 2 * 54.45 = 108.9 cm²

Therefore, the surface area = 108.9 cm²

Please brainlist my answer, if helpful!