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Two concentric circles are of radii 13 cm and 5 cm. Find the length of the chord of the larger circle which touches thesmaller circle at a point. |
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Answer» Step-by-step explanation: LET two CIRCLES have the same centre O and AB is a chord of the larger circle touching the smaller circle at C. OA=5cm and OC=3cm Now, As we know that the tangent at any point of a circle is perpendicular to the radius through the point of contact. Therefore, In △OAC, OA²=OC²+AC (By pythagoras theorem) ⇒AC²=OC²-OA² AC²= 5²-3² Ac =4cm Since perpendicular drawn from the centre of circle bisects the chord. Therefore, AB=2AC ⇒AB=2×4=8CM Hence the length of the chord is 8cm |
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