Two coins are tossed simultaneously. The probability of getting atmost

1.	Two coins are tossed simultaneously. The probability of getting atmost one head isA. \(\frac{1}{4}\)B. \(\frac{3}{4}\)C. \(\frac{1}{2}\)D. \(\frac{1}{4}\)
Answer» When two coins are tossed simultaneously then the possible outcomes obtained are {HH, HT, TH, and TT}. Here H denotes head and T denotes tail. Therefore, a total of 4 outcomes obtained on tossing two coins simultaneously. The favourable outcome of getting at most one head are HT, TH, and TT. So, the probability of getting at most one head is 3/4

Two coins are tossed simultaneously. The probability of getting atmost one head isA. \(\frac{1}{4}\)B. \(\frac{3}{4}\)C. \(\frac{1}{2}\)D. \(\frac{1}{4}\)

Answer»

When two coins are tossed simultaneously then the possible outcomes obtained are {HH, HT, TH, and TT}.

Here H denotes head and T denotes tail.

Therefore, a total of 4 outcomes obtained on tossing two coins simultaneously.

The favourable outcome of getting at most one head are HT, TH, and TT.

So, the probability of getting at most one head is 3/4

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Two coins are tossed simultaneously. The probability of getting atmost one head isA. \(\frac{1}{4}\)B. \(\frac{3}{4}\)C. \(\frac{1}{2}\)D. \(\frac{1}{4}\)

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