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Two coils of self inductance 100 mH and 400 mH are placed very closed to each other. Find maximum mutual inductance between the two when 4 A current passes through them.A. 200mHB. 300mHC. `100sqrt(2)mH`D. none of these |
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Answer» Correct Answer - A Maximum mutual inductance: `M=sqrt(L_(1)L_(2))=200mH`. |
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