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Two coils have a mutual inductance of 0.01 H. The current in the first coil changes according to equation, I = 5 sin 200`pi`t. The maximum value of emf induced in the second coil isA. `10piV`B. `0.1piV`C. `piV`D. `0.01piV` |
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Answer» Correct Answer - A Given, mutual inductance in the coil, M = 0.01 H and current in coil , I = 5sin200 `pi`t. Emf induced in secondary coil is given, `e=M(dl)/(dt)` putting the value in above relation `e=0.01xxd/(dt)(5sin200pit)` `=0.01xx5xx200picos200pit=10picos200pit` Compairing the above equation with the general equation of induced emf, which is represented as, `e=e_(0)cosomegat` where, `e_(0)` is the maximum value of the emf. `therefore` In the question, the maximum value of emf induced in the coil is, `e_(0)=10piV` |
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