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Two coils have a mutual inductance of 0.005H. The current changes in the first coil according to equation I=I_0 sin omegat ,where I_0 = 10A and omega = 100pirad/sec. The maximum value of emf in the second coil is ___ |
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Answer» SOLUTION :Induced emf `epsilon=-M(dI)/(dt) =-M d/(dt)(t^2 e^(-t))` `=-M I_0 omega cos omegat` When `cos omegat =-1` , then emf will be maximum `THEREFORE epsilon_"maximum"=0.005xx10xx100xx(-1)=5piV` |
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