1.

Two coils have a mutual inductance of 0.005H. The current changes in the first coil according to equation I=I_0 sin omegat ,where I_0 = 10A and omega = 100pirad/sec. The maximum value of emf in the second coil is ___

Answer»

`2pi`
`5PI`
`pi`
`4PI`

SOLUTION :Induced emf `epsilon=-M(dI)/(dt) =-M d/(dt)(t^2 e^(-t))`
`=-M I_0 omega cos omegat`
When `cos omegat =-1` , then emf will be maximum
`THEREFORE epsilon_"maximum"=0.005xx10xx100xx(-1)=5piV`


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