Two coils are wound side by side on a paper-tube former. An e.m.f. of

1.	Two coils are wound side by side on a paper-tube former. An e.m.f. of 0.25 V is induced in coil A when the flux linking it changes at the rate of 103 Wb/s. A current of 2 A in coil B causes a flux of 10−5 Wb to link coil A. What is the mutual inductance between the coils ?
Answer» Induced e.m.f. in coil A is e = N₁(dΦ/dt) where N₁ is the number of turns of coil A. ∴ 0.25 = N₁ × 10⁻³ ∴ N₁ = 250 Now, flux linkages in coil A due to 2 A current in coil B = 250 × 10⁻⁵ ∴ M = flux linkages in coil A/current in coil B = 250 × 10⁻⁵ /2 = 1.25 mH

Two coils are wound side by side on a paper-tube former. An e.m.f. of 0.25 V is induced in coil A when the flux linking it changes at the rate of 103 Wb/s. A current of 2 A in coil B causes a flux of 10−5 Wb to link coil A. What is the mutual inductance between the coils ?

Answer»

Induced e.m.f. in coil A is e = N₁(dΦ/dt) where N₁ is the number of turns of coil A.

∴ 0.25 = N₁ × 10⁻³

∴ N₁ = 250 Now, flux linkages in coil A due to 2 A current in coil B = 250 × 10⁻⁵

∴ M = flux linkages in coil A/current in coil B = 250 × 10⁻⁵ /2 = 1.25 mH

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Two coils are wound side by side on a paper-tube former. An e.m.f. of 0.25 V is induced in coil A when the flux linking it changes at the rate of 103 Wb/s. A current of 2 A in coil B causes a flux of 10−5 Wb to link coil A. What is the mutual inductance between the coils ?

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