Saved Bookmarks
| 1. |
Two coils, A and B, are linked such that emf ℰ is induced in B when the current in A is changing at the rate I. If i current is now made to flow in B, the flux linked with A will be (a) (ℰ/I)i (b) ℰi I (c) (ℰ I)i (d) iI/ℰ |
|
Answer» Correct Answer is: (a) (ℰ/I)i Let M = mutual inductance between A and B. eB = M (diA/dt) or ℰ = MI or M = ℰ / I ϕA = MiB = (ℰ / I) i. |
|