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Two coils – 1 and 2 – are mounted co axially as shown in the figure. The resistance of the two coils are `R_(1)` and `R_(2)` and their self inductances are `L_(1)` and `L_(2)` respectively. Switch S is closed at time t = 0 to connect the coil 1 to an ideal cell of emf V. It is observed that by the time current reaches its steady value in coil 1, the quantity of charge that flows in coil 2 is `Q_(0)`. Calculate the mutual inductance (M) between the two coils. |
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Answer» Correct Answer - `(R_(1)R_(2)Q_(0))/(V)` |
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