Saved Bookmarks
| 1. |
Two cities `A and B` are connected by a regular bus service with buses plying in either direction every `T` seconds. The speed of each bus is uniform and equal to `V_b`. A cyclist cycles from `A to B` with a uniform speed of `V_c`. A bus goes past the cyclist in `T_1` second in the direction `A to B` and every `T_2` second in the direction `B to A`. ThenA. `T_1 = (V_b T)/(V_b + V_c)`B. `T_2 = (V_b T)/(V_b - V_c)`C. `T_1 = (V_b T)/(V_b - V_c)`D. `T_2 = (V_b T)/(V_b + V_c)` |
|
Answer» Correct Answer - C::D (c.,d.) Distance between two buses on road is `V_bT`. For `A to B` direction : Distance = Relative velocity xx Time `V_b T=(V_b - V_c)T_1 rArr T_1 = (V_b T)/(V_b - V_c)` For `B to A` direction : `V_b T =(V_b + V_c)T_2 rArr T_2 = (V_b T)/(V_b + V_c)`. |
|