Two chords AB and CD of a circle intersect at a point outside the circle. Prove thata△PAC~△PDBbPA.PB=PC.PD

Two chords AB and CD of a circle intersect at a point outside the circ

1.	Two chords AB and CD of a circle intersect at a point outside the circle. Prove thata△PAC~△PDBbPA.PB=PC.PD
Answer» Two chords AB and CD of a circle intersect at a point outside the circle. Prove that $(a) △ PAC ~ △ PDB (b) PA . PB = PC . PD$