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Two charges q_1 and q_2 are placed on the X-axis at pointx=-a and x =+a respectively. a. How must q_1 and q_2 be related for the net electrostatic force on a charge Q at x=+(a)/(2)to be zero? b. Repeat (a) but with +Q at x =+(3a)/( 2) |
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Answer» Solution :Data supplied ` (##JYT_AJP_AIO_PHY_XII_C01_SLV_014_S01.png" width="80%"> Net force at Q is zero Here force due to `q_1` acts towards left and that due to` q_2` towards right . Hence the RESULTANT forceon Q is `F_(Qq_1) -F_(Qq_2) =0` i.e., `F_(Qq_1) = F_(Qq_2) ` `(1)/( 4PI in _0) (Qq_1)/( (a+(a)/(2)))=(1)/( 4pi in _0) .(Qq_2)/( (a)/(2)^(2)) =( q_1)/(( 9a^(2))/( 4)) =(q^(2))/( (a^(2))/( 4)) ` ` (q_1)/( 9) =q_2"" therefore q_1 =9q_2` b.` (##JYT_AJP_AIO_PHY_XII_C01_SLV_014_S02.png" width="80%"> Here force due to `q_1 and q_2` both act towards right. Hence the resultant force on Q is `F_(Qq_1) +F_(Qq_2) =0` ` F_(Qq_1) =-F_(Qq_2) ` ` (1)/( 4pi in _0).( Qq_1)/( (a+(3a)/(2))^(2)) =(1)/( 4pi in _0) .(Qq_2)/( (a)/(2))^(2) =( q_1)/((25a^(2))/( 4)) =(-q_2)/( (a^(2))/( 4))` ` (q,)/( 25) =q_2 "" q_1 =-25 q_2` |
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