1.

Two charges of10 mu Cand 20 muCrespectively are placed at points A and Brespectively separated by a distance of 60 cm . The distance of the point P fromA, where the net electric field is zero, is(##U_LIK_SP_PHY_XII_C01_E04_021_Q01.png" width="80%">

Answer»

20cm
30 cm
40 cm
15 cm

Solution :If A =R cm , then ` (q_A)/(r^(2)) =(q_B)/((60-r)^(2)) rArr (10muC )/(r^(2)) =(40 MU C )/((60-r)^(2)) rArr r= 20 cm `


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