two charges of magnitude 5nC and -2nC are placed at points (2,0,0) and

1.	two charges of magnitude 5nC and -2nC are placed at points (2,0,0) and (x,0,0) in a region of space where there is no external field . If electrostatic potential of the system is -0.5 j ,find the value of x
Answer» Explanation: For a square ABCD, OA=OB=OC=OD=r As charge 5μC is placed on CENTER O so EVERY point A,B,C and D have same POTENTIAL V=5k/r. Thus potential difference (dV) between A and B will be zero. Work done W=qdV=1(0)=0 solution

two charges of magnitude 5nC and -2nC are placed at points (2,0,0) and (x,0,0) in a region of space where there is no external field . If electrostatic potential of the system is -0.5 j ,find the value of x

Answer»

Explanation:

For a square ABCD, OA=OB=OC=OD=r

As charge 5μC is placed on CENTER O so EVERY point A,B,C and D have same POTENTIAL V=5k/r.

Thus potential difference (dV) between A and B will be zero.

Work done W=qdV=1(0)=0

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two charges of magnitude 5nC and -2nC are placed at points (2,0,0) and (x,0,0) in a region of space where there is no external field . If electrostatic potential of the system is -0.5 j ,find the value of x​

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two charges of magnitude 5nC and -2nC are placed at points (2,0,0) and (x,0,0) in a region of space where there is no external field . If electrostatic potential of the system is -0.5 j ,find the value of x