Two charges +3.2×10−19 C and −3.2×10−19 C placed at 2.4 oA apart to form an eletric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is

Two charges +3.2×10−19 C and −3.2×10−19 C placed at 2.4 oA apa

1.	Two charges +3.2×10−19 C and −3.2×10−19 C placed at 2.4 oA apart to form an eletric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is
Answer» Two charges $+ 3.2 \times 10^{- 19} C$ and $- 3.2 \times 10^{- 19} C$ placed at $2.4 o A$ apart to form an eletric dipole. It is placed in a uniform electric field of intensity $4 \times 10^{5} volt/m$ . The electric dipole moment is

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Two charges +3.2×10−19 C and −3.2×10−19 C placed at 2.4 oA apart to form an eletric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is

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