Two charged balls are attached by silk threads of length l to the same point. Their velocity is K√x, where K is a constant and x is the distance between the balls, x is very small in comparison to l. The rate of leakage of charge in 10−5 C/s is (take lmg=10, K=4√2)

Two charged balls are attached by silk threads of length l to the same

1.	Two charged balls are attached by silk threads of length l to the same point. Their velocity is K√x, where K is a constant and x is the distance between the balls, x is very small in comparison to l. The rate of leakage of charge in 10−5 C/s is (take lmg=10, K=4√2)
Answer» Two charged balls are attached by silk threads of length $l$ to the same point. Their velocity is $\frac{K}{\sqrt{x}}$ , where $K$ is a constant and $x$ is the distance between the balls, $x$ is very small in comparison to $l$ . The rate of leakage of charge in $10^{- 5} C/s$ is (take $\frac{l}{m g} = 10, K = 4 \sqrt{2}$ )

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Two charged balls are attached by silk threads of length l to the same point. Their velocity is K√x, where K is a constant and x is the distance between the balls, x is very small in comparison to l. The rate of leakage of charge in 10−5 C/s is (take lmg=10, K=4√2)

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