1.

Two cells are connected in series and e.m.f. of combination is found to balance against length of 450 cm ofpotentiometer wire. Whentthetwo cells are connected in parallel emf of combination balances against50 cm length of wire. The ratio of e.m.f. of two cells is

Answer»

2.25
1.55
1.25
2.55

Solution :`(E_(1))/(E_(2))=(l_(1)+l_(2))/(l_(1)-l_(2))=(450+50)/(450-50)=5/4=1.25`


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